thenInWorkerThread传递的参数[]里是什么作用？

  return asyncSystem.all(std::move(resolvedBuffers))
      .thenInWorkerThread(
          [pResult = std::move(pResult)](
              std::vector<ExternalBufferLoadResult>&& loadResults) mutable {
            for (auto& bufferResult : loadResults) {
              if (!bufferResult.success) {
                pResult->warnings.push_back(
                    "Could not load the external gltf buffer: " +
                    bufferResult.bufferUri);
              }
            }
            return std::move(*pResult.release());
          });
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修改:smthxes FROM 27.208.36.*
FROM 27.208.36.*

带初始化的lambda 捕获表达式吧，前面的pResult 是只在lambda范围内有效的名字，后面那个pResult是被捕获的外部名字。要是在=,&之外添加&&表示move，就不用这么折腾了。
https://en.cppreference.com/w/cpp/language/lambda
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FROM 222.129.50.*

谢谢
【 在 z16166 的大作中提到: 】
: lambda
: https://docs.microsoft.com/en-us/cpp/cpp/lambda-expressions-in-cpp?view=msvc-170
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FROM 27.208.36.*