那不是调用的interfacesEqual()吗？查一下这个的实现

而且是不需要比较大小的，只需要比较是否相同/相等。

你也可以调用这个android::hardware::interfacesEqual()函数

/**
* Returns whether two interfaces represent the same interface. References to interfaces in the same
* process will always be equivalent. However, in order to compare a service that is a proxy to a
* different process, its underlying structure may have to be checked.
*/
bool interfacesEqual(const sp<::android::hidl::base::V1_0::IBase>& left,
                     const sp<::android::hidl::base::V1_0::IBase>& right);


bool interfacesEqual(const sp<IBase>& left, const sp<IBase>& right) {
    if (left == nullptr || right == nullptr || !left->isRemote() || !right->isRemote()) {
        return left == right;
    }
    return getOrCreateCachedBinder(left.get()) == getOrCreateCachedBinder(right.get());
}

【 在 bihai 的大作中提到: 】
: 刚查到，在安卓代码库里面有个例子Thermal.cpp
: using ::android::hardware::interfacesEqual;
: // std::vector<CallbackSetting> callbacks_;
: ...................
--
修改:z16166 FROM 221.218.160.*
FROM 221.218.160.*