下面的也能跑。结果还是“对”的。
闭包里保存引用和指针得万分小心

#include <iostream>
#include <memory>
#include <vector>
#include <functional>

class MyClass {
public:
    MyClass(int i):m(i) {
        std::cout << "----MyClass::MyClass() " << m << std::endl;
    }
    void member_function() {
        std::cout << "****I am still alive! " << m << std::endl;
    }
    ~MyClass() {
        std::cout << "----MyClass::~MyClass() " << m << std::endl;
    }
    int m;
};

int main() {

    std::vector<std::function<void()>> v_f;
    int* p = new int[100];
    {
        for (auto& i : { 10}) {
            
            MyClass my_class{i};
            auto lambda = [&my_class,p,i]() {
                my_class.member_function();
                p[i] = i;
                };
            std::cout << i << " lambda name() = "    << typeid(lambda).name() << std::endl;
            std::cout << i << " lambda address() = " << &lambda << std::endl;

            v_f.push_back(lambda);

        }
    }
    std::cout << "******************" << std::endl;
    delete[] p;

    for (auto& task : v_f) {  
        task();
    }
    std::cout << p[10] << std::endl;

    return 0;
}【 在 MyWorkLife 的大作中提到: 】
: 你这个例子正好说明问题
: 不像前面例子里面c++ lambda引用一个已经析构的空悬对象
: python对于保持对象生存周期毫无压力
: ...................
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