已知一个List<String> 比如

assignee_1 = [ "t101", "sPQ9527", "Foxconn", "zPQ1024", "BYD", "System" ]

以上作为参数，查询系统得到如下结果：

assignee_0 = { "t101":"tangseng 101", "sPQ9527":"sunwukong PQ9527", "zPQ1024":"zhubajie PQ1024" }

问题：

由以上两个List，怎样得到第三个List：

assignee_2 = [ "tangseng 101", "sunwukong PQ9527", "Foxconn", "zhubajie PQ1024", "BYD", "System" ]
不考虑顺序
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FROM 223.104.61.*

感觉也许你该多刷刷leetcode的简单题目。。。
【 在 townhope 的大作中提到: 】
: 已知一个List<String> 比如
: assignee_1 = [ "t101", "sPQ9527", "Foxconn", "zPQ1024", "BYD", "System" ]
: 以上作为参数，查询系统得到如下结果：
: ...................
--
FROM 211.144.19.*

~ $ amm3
Loading...
Welcome to the Ammonite Repl 2.5.2 (Scala 3.1.1 Java 17.0.3)
@ val xs = List("t101", "sPQ9527", "Foxconn", "zPQ1024", "BYD", "System")
xs: List[String] = List("t101", "sPQ9527", "Foxconn", "zPQ1024", "BYD", "System")

@ val m = Map("t101" -> "tangseng 101", "sPQ9527" -> "sunwukong PQ9527", "zPQ1024" -> "zhubajie PQ1024")
m: Map[String, String] = Map("t101" -> "tangseng 101", "sPQ9527" -> "sunwukong PQ9527", "zPQ1024" -> "zhubajie PQ1024")

@ xs.map(x => m.getOrElse(x, x))
res2: List[String] = List("tangseng 101", "sunwukong PQ9527", "Foxconn", "zhubajie PQ1024", "BYD", "System")

【 在 townhope 的大作中提到: 】
: 已知一个List<String> 比如
: assignee_1 = [ "t101", "sPQ9527", "Foxconn", "zPQ1024", "BYD", "System" ]
: 以上作为参数，查询系统得到如下结果：
: ...................
--
FROM 113.83.185.*

看错题了，那你这个转成map好搞一点
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FROM 36.112.12.*

leetcode不屑这种题
【 在 Xjt 的大作中提到: 】
: 感觉也许你该多刷刷leetcode的简单题目。。。
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FROM 112.96.51.*