肯定是严格相等，也就是手动纸笔去验算，也能验算OK。

from numba import jit
num_max = 101
print ('test')
@jit
def foo():
    s=0
    for a in range(2,num_max):
        
        for b in range(a+1,num_max):
            #print(a,b)
            for c in range(b+1,num_max):
                for d in range(c+1,num_max):
                    for e in range(d+1,num_max):
                        for f in range(e+1,num_max):
                            for g in range(f+1,num_max):
                                for h in range(g+1,num_max):
                                    for i in range(h+1,num_max):
                                        for j in range(i+1,num_max):
                                            if a*b*c*d*e*f*g*h*i*j==  b*c*d*e*f*g*h*i*j+ \
                                                                    a*  c*d*e*f*g*h*i*j+ \
                                                                    a*b*  d*e*f*g*h*i*j+ \
                                                                    a*b*c*  e*f*g*h*i*j+ \
                                                                    a*b*c*d*  f*g*h*i*j+ \
                                                                    a*b*c*d*e*  g*h*i*j+ \
                                                                    a*b*c*d*e*f*  h*i*j+ \
                                                                    a*b*c*d*e*f*g*  i*j+ \
                                                                    a*b*c*d*e*f*g*h*  j+ \
                                                                    a*b*c*d*e*f*g*h*i:
                                                s +=1
                                                print(s,a,b,c,d,e,f,g,h,i,j)

foo()

【 在 tiewuzi 的大作中提到: 】
: 是要严格等于1还是一定精度范围内?
: 严格相等的话光是验证就挺费事的
:
--
修改:z16166 FROM 123.119.160.*
FROM 123.119.160.*