dn = 888866
if -9999<= dn <=-1000 or 1000<= dn <=9999:
    print("You entered a 4-digit number")
elif -999<= dn <=-100 or 100<= dn <=999:
    print("You entered a 3-digit number")
elif -99<= dn <=-10 or 10<= dn <=99:
    print("You entered a 2-digit number")
elif -9<= dn <=9:
    print("You entered a 1-digit number"
else:
    print("Wrong number!")


【 在 kisspanda 的大作中提到: 】
: 整半天了也没整明白，老是报错……
:  要求：编写一个Python程序，提示用户输入一个介入-9999和9999之间的整数，然后计算其总位数。最后，显示“You entered a N-digit number”，其中N为数字的总位数。
:  我写的：
: ...................
--
修改:javame FROM 124.78.15.*
FROM 124.78.15.*