from decimal import Decimal
def decimal_to_binary(decimal):
    # 处理整数部分
    integer_part = int(decimal)
    binary_integer = bin(integer_part)[2:]  # 去掉二进制前缀"0b"
    # bin()是一个内置函数，用于将整数转换为二进制字符串。它接受一个整数作为参数，并返回一个以"0b"开头的二进制字符串表示
    # 处理小数部分
    decimal_part = decimal - integer_part
    binary_decimal = ""
    precision = 23  # 设置小数部分的精度

    while decimal_part > 0 and precision > 0:
        decimal_part *= 2
        bit = int(decimal_part)
        binary_decimal += str(bit)
        decimal_part -= bit
        precision -= 1

    binary = binary_integer + "." + binary_decimal
    return binary

# 测试
decimal = Decimal('0.559999942779541015625000000000')
binary = decimal_to_binary(decimal)
print(str(decimal)+"转成二进制是："+binary)

decimal2 = Decimal('0.78')
binary2 = decimal_to_binary(decimal2)
print(str(decimal2)+"转成二进制是："+binary2)

from decimal import Decimal
def binary_to_decimal(binary):
    # 将二进制小数转换为十进制
    decimal = Decimal('0.0000')
    power = -1

    for bit in binary[2:]:
        #decimal += int(bit) * 2 ** power
        decimal += Decimal(int(bit)) * Decimal(2) ** power
        power -= 1

    #print(decimal)
    return  decimal
binary1 = "0.1000111101011100001010001111010111000010"#0.56
binary2= "0.11000111101011100001010"
print(binary2 +"转成十进制是："+str(binary_to_decimal(binary2)))

我用以上代码，先 十转二，再二转十。二进制保留23位。0.54 和0.56 完美符合预期。可是0.23和0.78，越转越大，没道理啊！0.45 和0.98，最后结果也不一致，有哪位能解释一下吗？谢谢
--
FROM 120.242.238.*