这里是错的吧，无法访问url。

function buildUrl() {

  let qs = "?debug=true";

          

  with(location){

    let url = href + qs;    

  }

          

  return url;

}

书里的说法也不对

Inside the with statement is a variable declaration for url,

which becomes part of the function’s context and can, therefore, be returne
d as the function value.
--
FROM 101.93.88.*