#include <iostream>

class A {
public:
  A(int a) : data_(a) {};
private:
  int data_ = 0;
};


template <typename PtrType>
struct Access {
     inline static PtrType ptr;
};

template <auto V>
struct PtrTaker {
    struct Transferer {
        Transferer() {
            Access<decltype(V)>::ptr = V;
        }
    };
    static Transferer tr;
};

template struct PtrTaker<&A::data_>;

int main() {
  A a{10};
  std::cout << a.*Access<int A::*>::ptr << std::endl;
  return 0;
}

a.*Access<int A::*>::ptr 是如何将a::data_的值或者地址 赋值给Access<int A::*>::ptr
这块没想明白，谢谢
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