https://wiki.sei.cmu.edu/confluence/display/c/DCL39-C.+Avoid+information+leakage+when+passing+a+structure+across+a+trust+boundary

这个页面上的
Noncompliant Code Example (memset())这个部分，有一句话

However, a conforming compiler is free to implement arg.b = 2 by setting the low-order bits of a register to 2, leaving the high-order bits unchanged and containing sensitive information.

这里的conforming是什么意思？

另外，既然前面对arg都memset为0了，这里arg.b中应该没有sensitive information了吧?
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