//下面代码是没办法执行完的，太诡异了，但是更诡异的事是a、b都volatile，更诡异的是线程2打印一下就能正常
public class t1 {
     static long a=0;    
     static long b=0;
    static long time;
public static void main(String[] s) {
    time=System.currentTimeMillis();
    
    new t1.th1().start();
    new t1.th2().start();
    System.out.println("start ..");
}
static class th1 extends Thread{
    public void run() {
        System.out.println("start a");
        while(a<100*100) {
            if(a==b)a++;
            System.out.println(a+"  "+b);
        }
        System.out.println(System.currentTimeMillis()-time);
        System.out.println("a is end");
    }
    
}
static class th2 extends Thread{
    public void run() {
        System.out.println("start b");
        while(a<100*100)
        {
            if(a>b)b++;
    //    System.out.println(a+"  "+b);  执行这条语句的话，能正常
        }
        System.out.println("b is end ");
        }
}
}
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