class Animal {
    sayHello() {}
}

class Fish extends Animal {
    const name = "goldfish";

    constructor() {
        super();
        this.hasBrain = true;
    }

    sayGoodbye() {}
}

let f = new Fish();

想要列出 f 的几个属性怎么做？希望实现这么一个 dir() 函数？

>> dir(f)
["sayHello", "name", "constructor", "sayGoodbye"]

我现在唯一想到的办法是递归遍历 f, f.__prototype__, ...
--
修改:hgoldfish FROM 59.60.25.*
FROM 59.60.25.*